document.write( "Question 94328: Please help me: It says to Complete the square to find the center of the radius of the given circle.Could you show me the steps in completing this.\r
\n" ); document.write( "\n" ); document.write( "A\"x%5E2%2By%5E2%2B6x-4y-3=0\"\r
\n" ); document.write( "\n" ); document.write( "B \"2x%5E2%2B2y%5E2-4x%2B8y-24=0\"\r
\n" ); document.write( "\n" ); document.write( "Thank you
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Algebra.Com's Answer #68665 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
A. Complete the square to find the centre and the radius.
\n" ); document.write( "\"x%5E2%2By%5E2%2B6x-4y-3+=+0\" Add 3 to both sides.
\n" ); document.write( "\"x%5E2%2By%5E2%2B6x-4y+=+3\" Group the like-terms together on the left side.
\n" ); document.write( "\"%28x%5E2%2B6x%29+%2B+%28y%5E2-4y%29+=+3\" Now complete the squares in the x- and y-terms. To do this, you add the square of half the x-coefficient and the square of half the y-coefficient to both sides of the equation.
\n" ); document.write( "For the x's this would be \"%286%2F2%29%5E2+=+9\" and for the y's this would be \"%28-4%2F2%29%5E2+=+4\", so we get:
\n" ); document.write( "\"%28x%5E2%2B6x%2B9%29+%2B+%28y%5E2-4y%2B4%29+=+3%2B9%2B4\" Factor the trinomials and simplify.
\n" ); document.write( "\"%28x%2B3%29%5E2+%2B+%28y-2%29%5E2+=+16\" Now compare this with the standard form for a circle with centre at (h, k) and radius r.
\n" ); document.write( "\"%28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2\" and you can see that the centre (h, k) is at (-3, 2) while the radius is \"sqrt%2816%29\" = 4.\r
\n" ); document.write( "\n" ); document.write( "Follow this approach on the second problem and see how you do.
\n" ); document.write( "If you still have problems, please re-post.
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