document.write( "Question 1071692: A boat travels 7 km upstream and 7km back. The time for the round trip is 4 hrs. The speed of the stream is 3 km/hr. What is the speed of the boat in still water? \n" ); document.write( "
Algebra.Com's Answer #686622 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A boat travels 7 km upstream and 7km back. The time for the round trip is 4 hrs. The speed of the stream is 3 km/hr. What is the speed of the boat in still water? \n" ); document.write( "Upstream DATA: \n" ); document.write( "dist = 7 km ; time = t hrs ; rate = 7/t km/hr \n" ); document.write( "----------- \n" ); document.write( "Downstream DATA: \n" ); document.write( "dist = 7 km ; time = 4-t hrs ; rate = 7/(4-t) km/hr \n" ); document.write( "------- \n" ); document.write( "Rate Equations: \n" ); document.write( "b - 3 = 7/t \n" ); document.write( "b + 3 = 7/(4-t) \n" ); document.write( "------------------------- \n" ); document.write( "Solve for \"t\":: \n" ); document.write( "[7/t]+3 = [7/(4-t)]-3 \n" ); document.write( "------ \n" ); document.write( "7/(4-t) - 7/t = 6 \n" ); document.write( "------------------------- \n" ); document.write( "[7t-7(4-t)]/(4t-t^2) = 6 \n" ); document.write( "------------------------------- \n" ); document.write( "14t-28 = 24t - 6t^2 \n" ); document.write( "-------------------------- \n" ); document.write( "6t^2 - 10t - 28 = 0 \n" ); document.write( "------- \n" ); document.write( "3t^2 - 5t -14 = 0 \n" ); document.write( "t = 3.15 hrs \n" ); document.write( "--- \n" ); document.write( "Solve for \"b\": \n" ); document.write( "b-3 = 7/t \n" ); document.write( "b = 7/3.15 + 3 \n" ); document.write( "boat speed = 5.22 km/hr \n" ); document.write( "---------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "---------------\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |