document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=94305>Question 94305</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many ounces of pure water must be added to 80oz. of a 35% salt solution to make a 14% salt solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #68657 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=68657\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How many ounces of pure water must be added to 80oz. of a 35% salt solution to make a 14% salt solution?<BR>\n" );
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document.write( "35% solution DATA;<BR>\n" );
document.write( "Amt = 80 oz ; amt of salt = 0.35*80 = 28 oz<BR>\n" );
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document.write( "Pure water DATA;<BR>\n" );
document.write( "Amt = x oz ; amt of salt = 0<BR>\n" );
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document.write( "14% solution DATA:<BR>\n" );
document.write( "Amt = 80+x oz ; amt of salt = 0.14(80+x) = 11.2 + 0.14x oz<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "salt + salt = salt in mixture<BR>\n" );
document.write( "28 + 0 = 11.2 + 0.14x<BR>\n" );
document.write( "0.14x = 16.8<BR>\n" );
document.write( "x = 120 oz (amount of pure water that must be added)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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