document.write( "Question 1071648: logx+log3-(log3x-1)=log4
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Algebra.Com's Answer #686543 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
what i think you are asking is:\r
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\n" ); document.write( "\n" ); document.write( "log(x) + log(3) - log(3x-1) = log(4)\r
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\n" ); document.write( "\n" ); document.write( "if so, you would do the following:\r
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\n" ); document.write( "\n" ); document.write( "subtract log(3) from both sides of the equation to get:\r
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\n" ); document.write( "\n" ); document.write( "log(x) - log(3x-1) = log(4) - log(3)\r
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\n" ); document.write( "\n" ); document.write( "since log(a) - log(b0 = log(a/b), this equation becomes:\r
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\n" ); document.write( "\n" ); document.write( "log(x/(3x-1)) = log(4/3)\r
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\n" ); document.write( "\n" ); document.write( "since log(a) = log(b) is true if and only if a = b, this equation becomes:\r
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\n" ); document.write( "\n" ); document.write( "x/(3x-1) = 4/3\r
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\n" ); document.write( "\n" ); document.write( "cross multiply to get:\r
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\n" ); document.write( "\n" ); document.write( "3x = 4 * (3x-1)\r
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\n" ); document.write( "\n" ); document.write( "sinmplify to get:\r
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\n" ); document.write( "\n" ); document.write( "3x = 12x - 4\r
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\n" ); document.write( "\n" ); document.write( "subtract 3x from both sides of the equation and add 4 to both sides of the equation to get:\r
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\n" ); document.write( "\n" ); document.write( "4 = 9x\r
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\n" ); document.write( "\n" ); document.write( "divide both sides of the equation by 9 and solve for x to get:\r
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\n" ); document.write( "\n" ); document.write( "x = 4/9\r
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\n" ); document.write( "\n" ); document.write( "that's your solution.
\n" ); document.write( "to confirm it's a good solution, replace x in the original equation with it and evaluate that equation to see if it's true.
\n" ); document.write( "it's true if the left side of the equation equals the right side of the equation.\r
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\n" ); document.write( "\n" ); document.write( "start with:\r
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\n" ); document.write( "\n" ); document.write( "log(x) + log(3) - log(3x-1) = log(4)\r
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\n" ); document.write( "\n" ); document.write( "replace x with 4/9 to get:\r
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\n" ); document.write( "\n" ); document.write( "log(4/9) + log(3) - log(3*4/9 - 1) = log(4)\r
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\n" ); document.write( "\n" ); document.write( "evaluate to get:\r
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\n" ); document.write( "\n" ); document.write( ".6020599913 = .6020599913\r
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\n" ); document.write( "\n" ); document.write( "since this equation is true, the solution is good.\r
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\n" ); document.write( "\n" ); document.write( "your solution is that x = 4/9.\r
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