document.write( "Question 1071621: Two investments totaling $64,500 produce an annual income of $3560. One investment yields 3% per year, while the other yields 8% per year. How much is invested at each rate? \n" ); document.write( "

Algebra.Com's Answer #686529 by addingup(3677) $\"\"$ $\"About$

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one investment: 3%, amount: x
\n" ); document.write( "the other: 8%, amount: 64,500-x because x is invested at 3%
\n" ); document.write( "0.03x+0.08(64,500-x) = 3,560
\n" ); document.write( "0.03x+5,160-0.08x = 3,560
\n" ); document.write( "-0.05x = -1,600 divide both sides by 0.05 and remember that -/- = +
\n" ); document.write( "x = 32,000 This is the amount invested at 3%
\n" ); document.write( "The amount invested at 8% is 64,500-32,000 = 32,500 \n" ); document.write( "

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