document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=13582>Question 13582</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you reduce the following problem into A+Bi form:<BR>\n" );
document.write( "(i/(1-i)) + ((1-i)/i)\r<BR>\n" );
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document.write( "I tried dividing the first and second part of the problem as separate entities but all I ended up with was ((1+i)/2) + (-i-1) and that didn't really help much. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6865 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6865\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> well assuming that ((1+i)/2) + (-i-1) is correct so far, you are nearly there...\r<BR>\n" );
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document.write( "we have 1/2 + i/2 + -i - 1 which becomes<BR>\n" );
document.write( "-1/2 - i/2\r<BR>\n" );
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document.write( "so, -1/2 - (1/2)i\r<BR>\n" );
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document.write( "jon<BR>\n" );
document.write( " </SPAN>\n" );
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