document.write( "Question 1071492: On Saturday morning, lynn walked for 2 hours and then ran for 45 minutes. If she ran twice as fast as she walked and she covered 14 miles altogether, then how fast did she walk? \n" ); document.write( "

Algebra.Com's Answer #686432 by math_helper(2461) $\"\"$ $\"About$

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Let w be the speed at which Lynn walked.
\n" ); document.write( "Then 2w is the speed at which Lynn ran.\r
\n" ); document.write( "\n" ); document.write( " (2hrs)(w mi/hr) + (45/60 hr)(2w mi/hr) = 14 mi\r
\n" ); document.write( "\n" ); document.write( "I'll drop the units while solving for w:
\n" ); document.write( " 2w + (45/60)(2w) = 14
\n" ); document.write( " 2w + 1.5w = 14
\n" ); document.write( " 3.5w = 14
\n" ); document.write( " w = 14/3.5
\n" ); document.write( " w = 4 mi/hr (her speed while walking)\r
\n" ); document.write( "\n" ); document.write( "This implies 2w = 8 mi/hr (her speed while running)
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\n" ); document.write( "Ans: Lynn walked at $\"+highlight%284%29+\"$ mi/hr
\n" ); document.write( "—\r
\n" ); document.write( "\n" ); document.write( "Check: 4mi/hr * 2hr + 8mi/hr*0.75hr = 8mi + 6mi = 14mi (ok)\r
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