document.write( "Question 94208: Factor 50x^3-90x^2 \n" ); document.write( "

Algebra.Com's Answer #68635 by bucky(2189) $\"\"$ $\"About$

You can put this solution on YOUR website!
Given:
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\n" ); document.write( "50x^3 - 90x^2
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\n" ); document.write( "Notice that 50 and 90 both have a common factor of 10 ... remove that factor and you get:
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\n" ); document.write( "10(5x^3 - 9x^2)
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\n" ); document.write( "Now both of the terms in the parentheses have x^2 as a common factor. (x^3 is the same as
\n" ); document.write( "x^2 times x so you can remove the x^2 and the x remains). Removing the x^2 from both terms
\n" ); document.write( "results in the factored form becoming:
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\n" ); document.write( "10x^2(5x - 9)
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\n" ); document.write( "and that is as far as you can factor it. The two terms inside the parentheses have no
\n" ); document.write( "common factors so nothing else can be done unless your instructor prefers that you factor
\n" ); document.write( "the 10 into 5*2 and the x^2 into x*x to give you:
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\n" ); document.write( "5*2*x*x(5x - 9)
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\n" ); document.write( "but this is not common practice. The common form is 10x^2(5x - 9).
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\n" ); document.write( "Hope this helps you to understand the problem.
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