document.write( "Question 1071365: Michelle has 2000 pounds in a bank account. each week she deposits a further 120 \r
\n" ); document.write( "\n" ); document.write( "Explain why the amount of money in her account after n weeks is given by \r
\n" ); document.write( "\n" ); document.write( "M=2000 + 120n puonds
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Algebra.Com's Answer #686327 by Theo(13342)\"\" \"About 
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she starts with 2000 pounds.
\n" ); document.write( "it doesn't matter what the value of n is, she will have at least 2000 pounds in the bank.
\n" ); document.write( "that becomes your fixed component of the equation.
\n" ); document.write( "when n = 0, what is in the account is 2000 pounds.
\n" ); document.write( "for each week after that, she deposits 120 pounds.
\n" ); document.write( "that becomes your incremental component of the equation.
\n" ); document.write( "that depends on the value of n.
\n" ); document.write( "when n = 0 there is no additional amount added to the account.
\n" ); document.write( "for each n thereafter an additional 120 pounds is added to the acocunt.
\n" ); document.write( "the total added is equal to 120 * n
\n" ); document.write( "after n weeks, 120 * n has been added into the account.
\n" ); document.write( "for example:
\n" ); document.write( "when n = 3, the account balance is as follows:
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document.write( "n       balance\r\n" );
document.write( "0       2000\r\n" );
document.write( "1       2000 + 120 = 2120\r\n" );
document.write( "2       2120 + 120 = 2240\r\n" );
document.write( "3       2240 + 120 = 2360\r\n" );
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\n" ); document.write( "the equation is 2000 + 120 * n
\n" ); document.write( "that becomes 2000 + 120 * 3
\n" ); document.write( "that becomes 2000 + 360
\n" ); document.write( "that becomes 2360\r
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\n" ); document.write( "\n" ); document.write( "the equation correctly determine what the balance in the account will be after n weeks.\r
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