document.write( "Question 1071365: Michelle has 2000 pounds in a bank account. each week she deposits a further 120 \r
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document.write( "Explain why the amount of money in her account after n weeks is given by \r
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document.write( "M=2000 + 120n puonds
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Algebra.Com's Answer #686327 by Theo(13342)![]() ![]() You can put this solution on YOUR website! she starts with 2000 pounds. \n" ); document.write( "it doesn't matter what the value of n is, she will have at least 2000 pounds in the bank. \n" ); document.write( "that becomes your fixed component of the equation. \n" ); document.write( "when n = 0, what is in the account is 2000 pounds. \n" ); document.write( "for each week after that, she deposits 120 pounds. \n" ); document.write( "that becomes your incremental component of the equation. \n" ); document.write( "that depends on the value of n. \n" ); document.write( "when n = 0 there is no additional amount added to the account. \n" ); document.write( "for each n thereafter an additional 120 pounds is added to the acocunt. \n" ); document.write( "the total added is equal to 120 * n \n" ); document.write( "after n weeks, 120 * n has been added into the account. \n" ); document.write( "for example: \n" ); document.write( "when n = 3, the account balance is as follows: \n" ); document.write( " \r\n" ); document.write( "n balance\r\n" ); document.write( "0 2000\r\n" ); document.write( "1 2000 + 120 = 2120\r\n" ); document.write( "2 2120 + 120 = 2240\r\n" ); document.write( "3 2240 + 120 = 2360\r\n" ); document.write( " \n" ); document.write( "the equation is 2000 + 120 * n \n" ); document.write( "that becomes 2000 + 120 * 3 \n" ); document.write( "that becomes 2000 + 360 \n" ); document.write( "that becomes 2360\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the equation correctly determine what the balance in the account will be after n weeks.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |