document.write( "Question 1071113: Mitchell invested part of his $14000 advance at 2% annual simple interest and the rest at 5% annual simple interest. his total yearly interest from both accounts was $580.\r
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document.write( "What is the amount invested at 2%?
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document.write( "What is the amount invested at 5%? \n" );
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Algebra.Com's Answer #686285 by Boreal(15235) You can put this solution on YOUR website! x at 2% \n" ); document.write( "14000-x at 5% \n" ); document.write( ".02x+.05(14000-x)=$580 \n" ); document.write( ".02x+700-.05x=$580 \n" ); document.write( "-0.03x=-120 \n" ); document.write( "x=$4000 at 2%=$80 \n" ); document.write( "14,000-x=$10000@5%=$500 \n" ); document.write( "Add to $580 \n" ); document.write( " \n" ); document.write( " |