document.write( "Question 1071323: A cargo plane left Rome and flew toward the airshow. A passenger plane left one hour later flying 100 mph faster in an effort to catch up to it. After three hours the passenger plane finally caught up. What was the cargo planes average speed? \n" ); document.write( "
Algebra.Com's Answer #686277 by Boreal(15235)\"\" \"About 
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speed of cargo plane=x
\n" ); document.write( "passenger plane's speed=x+100
\n" ); document.write( "time before same distance was 4 hours for cargo plane, 3 hours for passenger plane
\n" ); document.write( "cargo plane flew 4x miles; passenger plane 3(x+100) miles. The two are equal.
\n" ); document.write( "4x=3x+300
\n" ); document.write( "x=300 mph for cargo plane, flew 300 miles before passenger plane left and another 900 miles before caught.
\n" ); document.write( "x+100=400 mph for passenger plane, which flew 1200 miles in 3 hours before catching cargo plane.\r
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