document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1071325>Question 1071325</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write the standard form of the equation of the line described.\r<BR>\n" );
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document.write( "Through:(-3, -2), perpendicular to y=negative 3/5 x-5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #686275 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=686275\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perpendicular line has a slope that is the negative reciprocal of -3/5.  That would be +5/3<BR>\n" );
document.write( "point slope formula <BR>\n" );
document.write( "y-y1=m(x-x1), where m is slope and (x1,y1) the point<BR>\n" );
document.write( "y+2=(5/3)(x+3)<BR>\n" );
document.write( "y=(5/3)x+3<BR>\n" );
document.write( "-(5/3)x+y=3<BR>\n" );
document.write( "multiply by -3<BR>\n" );
document.write( "5x-3y=-9<BR>\n" );
document.write( "That does go through (-3,-2)<BR>\n" );
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document.write( " </SPAN>\n" );
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