document.write( "Question 1071305: In the equation x^2-y^2=8 if the value of y=-1, the value of X is\r
\n" ); document.write( "\n" ); document.write( "A. -3
\n" ); document.write( "B. +3
\n" ); document.write( "C. +-3
\n" ); document.write( " -
\n" ); document.write( "D. 9
\n" ); document.write( "

Algebra.Com's Answer #686272 by MathTherapy(10555)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "In the equation x^2-y^2=8 if the value of y=-1, the value of X is\r
\n" ); document.write( "\n" ); document.write( "A. -3
\n" ); document.write( "B. +3
\n" ); document.write( "C. +-3
\n" ); document.write( " -
\n" ); document.write( "D. 9
\n" ); document.write( "
All you need to do is just substitute - 1 for y
\n" ); document.write( "So,
\n" ); document.write( "Find x!
\n" ); document.write( "Why did you put x and X. It's one or the other as: \"x+%3C%3E+X\". \n" ); document.write( "
\n" );