document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1071292>Question 1071292</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two gasohol mixtures are available, one with 6.35% alcohol and the other with 11.28% alcohol. How many litres of the 6.35% mixture must be added to 25.0 L of the other mixture to make a final mixture containing 8.00% alcohol?<BR>\n" );
document.write( "Round the answer to one decimal place </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #686246 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=686246\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=number  of l needed.<BR>\n" );
document.write( ".0635x+(25)(.1128)=(25+x)(.08), the \"pure\" amount<BR>\n" );
document.write( ".0635+2.82=2+.08x<BR>\n" );
document.write( "-0.0165x=-.82<BR>\n" );
document.write( "x=49.7 liters.<BR>\n" );
document.write( "Rough check.<BR>\n" );
document.write( "This is about twice as much of the lower amount, and the lower amount is 1.65% less concentrated and the higher amount is 3.3% more concentrated.  This makes sense. </SPAN>\n" );
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