document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1071264>Question 1071264</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist has a solution that is 65&#8203;% acid and another that is 45&#8203;% acid.  How many liters of each should he mix to obtain 300 liters of a solution that is 60&#8203;% &#8203;acid? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #686214 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=686214\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=65%<BR>\n" );
document.write( "300-x=45%<BR>\n" );
document.write( ".65x+(.45)(300-x)=.60(300)<BR>\n" );
document.write( ".65x+135-.45x=180<BR>\n" );
document.write( ".20x=45<BR>\n" );
document.write( "x=225 liters 65% which is 146.25 l pure acid<BR>\n" );
document.write( "300-x=75 liters 45%=33.75 l pure acid<BR>\n" );
document.write( "Those two add to 180 l pure acid, or 60% of 300 l </SPAN>\n" );
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