document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1071263>Question 1071263</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist has a solution that is 65&#8203;% acid and another that is 45&#8203;% acid.  How many liters of each should he mix to obtain 300 liters of a solution that is 60&#8203;% &#8203;acid? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #686213 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=686213\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> one is 65%, let the amount be x<BR>\n" );
document.write( "the other is 45%, and since the total is 300, this amount will be 300-x<BR>\n" );
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document.write( "0.65x+0.45(300-x) = 0.60(300)<BR>\n" );
document.write( "0.65x+135-0.45x = 180<BR>\n" );
document.write( "0.20x = 45<BR>\n" );
document.write( "x = 225<BR>\n" );
document.write( "He needs 225 liters of the 65% solution and 300-225 = 75 liters of the 45% solution.<BR>\n" );
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document.write( "common sense quick check: What is the end result he's looking for? A 60% solution. Which is closest to 60, 65 or 45? It's 65, so it makes sense that you would need a larger amount of the 65% solution. </SPAN>\n" );
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