document.write( "Question 1071256: Stacy and Heather are 20 miles apart and walk towards each other along the same route. Stacy walks at constant rate that is 1 mile per hour fast than heather's constant rate of 5 miles/hour. If Heather starts her journey 24 minutes after Stacy, how far from the original destination has Heather walked when the two meet?.
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Algebra.Com's Answer #686191 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! How far does Stacy get in \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "-------------------- \n" ); document.write( "After \n" ); document.write( " \n" ); document.write( "and you start a stopwatch to \n" ); document.write( "measure time \n" ); document.write( "------------------------------ \n" ); document.write( "Let \n" ); document.write( "to walk utill they meet \n" ); document.write( "------------------------------ \n" ); document.write( "Heather's equation: \n" ); document.write( "(1) \n" ); document.write( "Stacy's equation: \n" ); document.write( "(2) \n" ); document.write( "------------------------ \n" ); document.write( "Plug (1) into (2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "------------------------- \n" ); document.write( "In \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "------------------ \n" ); document.write( "Heather walked 8 miles from her original \n" ); document.write( "destination until they meet \n" ); document.write( "------------------------- \n" ); document.write( "check: \n" ); document.write( "Stacy must have walked \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So Stacy walked a total of \n" ); document.write( "and added to Heather's distance, \n" ); document.write( " \n" ); document.write( "OK\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |