document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=94280>Question 94280</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the perimeter of a lot with sides measuring 5 sqr root 50, 3 sqr root 18, 3 sqr root 8, and 2 sqr root 27 yards </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #68614 by </B><A HREF=/tutors/aboutme.mpl?userid=jayanthihemkos@yahoo.com><B>jayanthihemkos@yahoo.com(87)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jayanthihemkos@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=68614\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the perimeter of a lot with sides measuring 5 sqr root 50, 3 sqr root 18, 3 sqr root 8, and 2 sqr root 27 yards\r<BR>\n" );
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document.write( "Perimeter is the sum of all sides.\r<BR>\n" );
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document.write( "5 sqr root 50+ 3 sqr root 18+ 3 sqr root 8+and 2 sqr root 27 yards\r<BR>\n" );
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document.write( "5 sqr root 25*2 + 3sqr root of 9*2 +3 sqr root of 4*2 + 2 sqr  9*3\r<BR>\n" );
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document.write( "5*5sqr root of 2 +3*3 sqr root of 2 + 3*2 sqr root of 2 + 2*3 sqr root of 3\r<BR>\n" );
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document.write( "25 sqr root of 2 + 9 sqr root of 2 + 6 sqr root of 2 + 6 sqr root of 3\r<BR>\n" );
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document.write( " (25 + 9 + 6 )sqr root of 2 + 6 sqr root of 3\r<BR>\n" );
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document.write( "(40 sqr root of 2 + 6 sqr root of 3)yards\r<BR>\n" );
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