document.write( "Question 1071216: Reena rode her skateboard to her uncle's house, 12 miles away. A wheel broke just as she arrived, so Reena borrowed her uncle's bicycle to return home. Traveling by bicycle, she was able to go twice as fast, and returned home in 2 hours less time than it took to go to her uncle's house. How long did it take Reena to get home on the bicycle? \n" ); document.write( "

Algebra.Com's Answer #686135 by ikleyn(52776) $\"\"$ $\"About$

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\n" ); document.write( "Reena rode her skateboard to her uncle's house, 12 miles away. A wheel broke just as she arrived, so Reena borrowed
\n" ); document.write( "her uncle's bicycle to return home. Traveling by bicycle, she was able to go twice as fast, and returned home in 2 hours less time
\n" ); document.write( "than it took to go to her uncle's house. How long did it take Reena to get home on the bicycle?
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\n" ); document.write( "\n" ); document.write( "More short and straightforward solution:\r
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document.write( "Let   s = her speed skateboarding to uncle's house\r\n" );
document.write( "Then 2s = her speed biking home\r\n" );
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document.write( "Let   t = time in hrs to skateboard to uncle's house\r\n" );
document.write( "Then  t - 2 = time in hrs to return home by bike\r\n" );
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document.write( "The distance to there d = st.\r\n" );
document.write( "The distance back     d = 2s*(t-2).\r\n" );
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document.write( "The distance is the same:  st = 2s*(t-2)   --->  cancel the factor s in both sides  --->\r\n" );
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document.write( "t = 2(t-2)  -->  t = 2t - 4  --->  t = 4.\r\n" );
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document.write( "Thus the time skateboarding is 4 hours.\r\n" );
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document.write( "Hence, the time bicycling is 4 - 2 = 2 hours.\r\n" );
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