document.write( "Question 1071165: Solve the equation (2 cos θ + 1)(tan θ − 1) = 0 for 0 ≤ θ ≤ 2π \n" ); document.write( "
Algebra.Com's Answer #686115 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
The equation is true if either of these is true:
\n" ); document.write( "\"+2%2Acos%28+theta+%29+%2B+1+=+0+\"
\n" ); document.write( "\"+2%2Acos%28+theta+%29+=+-1+\"
\n" ); document.write( "(1) \"+cos%28+theta+%29+=+-1%2F2+\"
\n" ); document.write( "OR
\n" ); document.write( "\"+tan%28+theta+%29+-+1+=+0+\"
\n" ); document.write( "(2) \"+tan%28+theta+%29+=+1+\"
\n" ); document.write( "--------------------------
\n" ); document.write( "(1) \"+theta+=+arc+cos%28+-1%2F2+%29+\"
\n" ); document.write( "(1) \"+theta+=+2.0944+\"
\n" ); document.write( "If I divide this by \"+pi+\" I get \"+2%2F3+\", which tells me
\n" ); document.write( "(1) \"+theta++=+%28+2%2Api+%29%2F3+\"
\n" ); document.write( "This is \"+theta+=+pi+-+pi%2F3+\"
\n" ); document.write( "The cosine is also negative for
\n" ); document.write( "\"+theta+=+pi+%2B+pi%2F3+\" which is
\n" ); document.write( "\"+theta+=+%28+4%2Api+%29%2F3+\"
\n" ); document.write( "--------------------------
\n" ); document.write( "(2) \"+theta+=+arc+tan%28+1+%29+\"
\n" ); document.write( "(2) \"+theta+=+.7854+\"
\n" ); document.write( "Dividing by \"+pi+\", I get \"+1%2F4+\", so
\n" ); document.write( "(2) \"+theta+=+pi%2F4+\"
\n" ); document.write( "The tan function is also positive in the 3rd quadrant, so
\n" ); document.write( "(2) \"+theta+=+pi+%2B+pi%2F4+\"
\n" ); document.write( "(2) \"+theta+=+%28+5%2Api+%29%2F4+\"
\n" ); document.write( "-----------------------------
\n" ); document.write( "The solutions are:
\n" ); document.write( "\"+theta+\" = \"+%28+2%2Api+%29%2F3+\", \"+%284%2Api%29%2F3+\", \"+pi%2F4+\", \"+%285%2Api%29%2F4+\"
\n" ); document.write( "If you can, get another opinion on this also \r
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