document.write( "Question 94213: Factor completely y^3-12y^2+36y \n" ); document.write( "
Algebra.Com's Answer #68611 by ankor@dixie-net.com(22740)\"\" \"About 
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Factor completely y^3-12y^2+36y
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\n" ); document.write( "You can see each term contains \"y\", so factor that out:
\n" ); document.write( "y(y^2 - 12y + 36)
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\n" ); document.write( "now you have a quadratic equation that can easily be factored so you have:
\n" ); document.write( "y (y-6)((y-6)
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