document.write( "Question 1071122: In a survey of women in a certain country (ages 20-29) the mean height 63.7 inches with a standard deviations 2.65 inches. What is the height that represent 85 perentile ? what is the height represent First quartile \n" ); document.write( "
Algebra.Com's Answer #686080 by stanbon(75887) ![]() You can put this solution on YOUR website! In a survey of women in a certain country (ages 20-29) the mean height 63.7 inches with a standard deviations 2.65 inches. \n" ); document.write( "What is the height that represent 85 percentile ? \n" ); document.write( "Find the z-value of the 85th percentile:: \n" ); document.write( "invNorm(0.85) = 1.0364 \n" ); document.write( "Find the corresponding height value:: \n" ); document.write( "h = z*s + u \n" ); document.write( "h = 1.0364*2.65 + 63.7 \n" ); document.write( "h = 66.47\" \n" ); document.write( "--------------------------------- \n" ); document.write( "What is the height represent First quartile? \n" ); document.write( "invNorm(0.25) = -0.6745 \n" ); document.write( "h = -0.6745*2.65+63.7 = 61.91\" \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "-------- \n" ); document.write( " |