document.write( "Question 1071110: The widths of two similar rectangles have a ratio of 2:6\r
\n" ); document.write( "\n" ); document.write( "The area of the smaller rectangle is 12 ft2.\r
\n" ); document.write( "\n" ); document.write( "What is the area of the larger rectangle?\r
\n" ); document.write( "\n" ); document.write( "I'm not sure how to go about this question. How do you solve it?
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Algebra.Com's Answer #686069 by MathTherapy(10557)\"\" \"About 
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\n" ); document.write( "The widths of two similar rectangles have a ratio of 2:6\r
\n" ); document.write( "\n" ); document.write( "The area of the smaller rectangle is 12 ft2.\r
\n" ); document.write( "\n" ); document.write( "What is the area of the larger rectangle?\r
\n" ); document.write( "\n" ); document.write( "I'm not sure how to go about this question. How do you solve it?
\n" ); document.write( "
The rectangles' sides are in a ratio of \"matrix%281%2C3%2C+1%3A3%2C+or%2C+1%2F3%29\" (smaller to larger), and so, their areas will be in a ratio of 12:32, or 1:9.
\n" ); document.write( "Now, since the smaller rectangle's area is 12 ft2, it follows that the larger rectangle's area will be: \"highlight_green%28matrix%281%2C4%2C+%229%2812%29%2C%22%2C+or%2C+108%2C+ft%5E2%29%29\" \n" ); document.write( "
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