document.write( "Question 1071110: The widths of two similar rectangles have a ratio of 2:6\r
\n" ); document.write( "\n" ); document.write( "The area of the smaller rectangle is 12 ft2.\r
\n" ); document.write( "\n" ); document.write( "What is the area of the larger rectangle?\r
\n" ); document.write( "\n" ); document.write( "I'm not sure how to go about this question. How do you solve it?
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Algebra.Com's Answer #686041 by addingup(3677)\"\" \"About 
You can put this solution on YOUR website!
ratio 2:6, the smaller is 12 so this is the 2 in the ratio.
\n" ); document.write( "2 = 12
\n" ); document.write( "6 = x
\n" ); document.write( "cross multiply:
\n" ); document.write( "2x = 72
\n" ); document.write( "x = 36
\n" ); document.write( "-------------------------------------
\n" ); document.write( "Check:
\n" ); document.write( "2+6 = 8
\n" ); document.write( "2/8 = 0.25
\n" ); document.write( "6/8 = 0.75
\n" ); document.write( "Now with the areas:
\n" ); document.write( "12+36 = 48
\n" ); document.write( "12/48 = 0.25
\n" ); document.write( "36/48 = 0.75 Correct.
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