document.write( "Question 1854: Solve by Factoring x^2=13x+48 \n" ); document.write( "

Algebra.Com's Answer #686 by longjonsilver(2297) $\"\"$ $\"About$

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you need everything on one side of the = sign so that it all equals zero. We then factorise ie write it as 2 things multiplied. The reason? Well, 2 things multipled that equal zero? One or the other of tem must be zero...this is how we find the solutions.\r
\n" ); document.write( "\n" ); document.write( "so, first, get all terms to the one side.... $\"x%5E2+-+13x+-+48+=+0\"$ . We then look at the -13 and the -48..we need 2 numbers that multiply to give the -48 and add to give -13. With practice you get better at this...try 16 and 3, well, -16 and +3...\r
\n" ); document.write( "\n" ); document.write( "now got $\"%28x-16%29%28x%2B3%29+=+0\"$ \r
\n" ); document.write( "\n" ); document.write( "so we can now say that either x-16=0 or x+3=0.\r
\n" ); document.write( "\n" ); document.write( "Hence x=16 or x=-3.\r
\n" ); document.write( "\n" ); document.write( "cheers
\n" ); document.write( "Jon. \n" ); document.write( "

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