document.write( "Question 1071040: I've tried for the last hour to solve this problem but I can't figure this out.
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\n" ); document.write( "\n" ); document.write( "A company conducted a marketing survey for families with young children and found that 124 families own a Nintendo DS and 186 families own a Nintendo Wii. If 20 own a Wii and a DS, how many own either a Wii or DS, but not both?
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Algebra.Com's Answer #685981 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
out of the families that have DS, 20 have both, so subtract them from the total to get 124 - 20 = 104.\r
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\n" ); document.write( "\n" ); document.write( "out of the families that have WII, 20 have both, so subtract them from the total to get 186 - 20 = 166.\r
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\n" ); document.write( "\n" ); document.write( "you now have 3 categories that are pure.\r
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\n" ); document.write( "\n" ); document.write( "104 own DS only.
\n" ); document.write( "266 own WII only.
\n" ); document.write( "20 own both.\r
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\n" ); document.write( "\n" ); document.write( "the total that own either a DS or a WII but not both are equal to 104 + 266 = 370.\r
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\n" ); document.write( "\n" ); document.write( "you have to subtract 20 from each category because it is included in both.
\n" ); document.write( "it is included in DS and it is included in WII.\r
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