document.write( "Question 1071016: Find the area of a parallelogram with vertices (0, 0), (3, 3), (4, 6), and (7, 9) using the formula which relates the area to the absolute value of the determinant of the matrix. \r
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Algebra.Com's Answer #685977 by Edwin McCravy(20054)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "To find out what order to taken the vertices, we plot\r\n" );
document.write( "the parallelogram:\r\n" );
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document.write( "To get the positive value of the area, take the coordinates \r\n" );
document.write( "going counter-clockwise around the polygon. Put the first\r\n" );
document.write( "pair of coordinate (0,0) again at the bottom:\r\n" );
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document.write( "To evaluate that determinant, add all the NW to SE diagonal\r\n" );
document.write( "products and subtract all the NE to SW diagonal products.\r\n" );
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document.write( "(0×3)+(3×9)+(7×6)+(4×0)-(0×3)-(3×7)-(9×4)-(6×0) =\r\n" );
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document.write( "  0  +  27 +  42 +   0 -   0 -  21 -  36 -   0  =\r\n" );
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document.write( " 12.  \r\n" );
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document.write( "Multiply by \"1%2F2\":\r\n" );
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document.write( "So \r\n" );
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document.write( "Edwin
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