document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1071028>Question 1071028</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mrs. Roza painted the top of a retagular table. The perimeter is 18 feet. The area of the table is 20 square feet. Which of the following could be the length and width of the tabletop?\r<BR>\n" );
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document.write( "a. 2ft, 9ft<BR>\n" );
document.write( "b. 10ft, 2ft<BR>\n" );
document.write( "c. 4ft, 5ft<BR>\n" );
document.write( "d. 9ft, 9ft\r<BR>\n" );
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document.write( "I am so confused on how to find the answer </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #685953 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=685953\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the dimensions from the given perimeter and area.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=system%282w%2B2L=18%2CwL=20%29 ALIGN=MIDDLE  ALT=\"system%282w%2B2L=18%2CwL=20%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=system%28w%2BL=9%2CwL=20%29 ALIGN=MIDDLE  ALT=\"system%28w%2BL=9%2CwL=20%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=L=9-w ALIGN=MIDDLE  ALT=\"L=9-w\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=w%289-w%29=20 ALIGN=MIDDLE  ALT=\"w%289-w%29=20\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-w%5E2%2B9w-20=0 ALIGN=MIDDLE  ALT=\"-w%5E2%2B9w-20=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=w%5E2-9w%2B20=0 ALIGN=MIDDLE  ALT=\"w%5E2-9w%2B20=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28w-4%29%28w-5%29=0 ALIGN=MIDDLE  ALT=\"%28w-4%29%28w-5%29=0\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "The way this situation works, one of the dimensions is 4 feet and the other dimension is 5 feet.  (If you were to first find w in terms of L and do the area formula substitution, you would have (L-4)(L-5)=0, so the same thing, same solutions - you might choose length as the bigger dimension.) </SPAN>\n" );
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