document.write( "Question 1070899: two cars leave towns 480 kilometers apart at the same time and travel toward each other. One car's rate is 20 kilometers per hour less than the other's. If they meet in 3 hours, what is the rate of the slower car?
\n" ); document.write( "Is this correct?
\n" ); document.write( "3r+3(r-20)=480
\n" ); document.write( "3r+3r-60=480
\n" ); document.write( "6r-60=480
\n" ); document.write( "6r/6=540/6
\n" ); document.write( "r=90 ???? rate of the slower car? and is there a way to check this myself? \n" ); document.write( "

Algebra.Com's Answer #685886 by Theo(13342) $\"\"$ $\"About$

You can put this solution on YOUR website!
should be.
\n" ); document.write( "if r = 90, then r - 20 = 70
\n" ); document.write( "the rate of the faster car is 90 kmph.
\n" ); document.write( "the rate of the slower car is 70 kmph.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "90 kmph * 3 hours = 270 km.
\n" ); document.write( "70 kmph * 3 hours = 210 km.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "if they meet in the middle somewhere, then the total km traveled has to be equal to 480.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "i think that's all you need to do to check your figures.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );