document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1070899>Question 1070899</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two cars leave towns 480 kilometers apart at the same time and travel toward each other.  One car's rate is 20 kilometers per hour less than the other's.  If they meet in 3 hours, what is the rate of the slower car?  <BR>\n" );
document.write( "Is this correct?<BR>\n" );
document.write( "3r+3(r-20)=480<BR>\n" );
document.write( "3r+3r-60=480<BR>\n" );
document.write( "6r-60=480<BR>\n" );
document.write( "6r/6=540/6<BR>\n" );
document.write( "r=90 ???? rate of the slower car?  and is there a way to check this myself? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #685883 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=685883\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x+3(x-20) = 480<BR>\n" );
document.write( "3x+3x-60 = 480<BR>\n" );
document.write( "6x = 540<BR>\n" );
document.write( "x = 90<BR>\n" );
document.write( "and the other:<BR>\n" );
document.write( "x-20 = 90-20 = 70<BR>\n" );
document.write( "-----------------------<BR>\n" );
document.write( "check:<BR>\n" );
document.write( "90+70 = 160<BR>\n" );
document.write( "480/160 = 3 Correct </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );