document.write( "Question 1070761: barbara's age is 5 years less than her brother's age if her age is increased by 3 times her brother's age the result is 51 years find each of their age. \n" ); document.write( "
Algebra.Com's Answer #685854 by josgarithmetic(39618)\"\" \"About 
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x, Barbara's age
\n" ); document.write( "y, Brother's age\r
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\n" ); document.write( "\n" ); document.write( "\"x=y-5\", her age is 3 times her brother's.
\n" ); document.write( "\"cross%283%28y-5%29%2By=51%29\", three times her age and her brother's age, given as 51----------wrong interpretation;
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\n" ); document.write( "If her age is increased by three times her brother's age
\n" ); document.write( "-should be \"x%2B3%28x%2B5%29\";
\n" ); document.write( "-the result is 51
\n" ); document.write( "\"highlight_green%28x%2B3%28x%2B5%29=51%29\"--------this will give Barbara's correct age, x.\r
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\n" ); document.write( "The rest of this below is wrong
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\n" ); document.write( "SOLVE
\n" ); document.write( "\"3y-15%2By=51\"
\n" ); document.write( "\"2y=51%2B15\"
\n" ); document.write( "\"2y=66\"
\n" ); document.write( "\"highlight%28y=33%29\"
\n" ); document.write( "-
\n" ); document.write( "\"highlight%28x=28%29\"
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