document.write( "Question 94184This question is from textbook
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\n" ); document.write( "log(little 2)64 = x
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Algebra.Com's Answer #68578 by jim_thompson5910(35256)\"\" \"About 
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\"log%282%2C%2864%29%29=x\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"log%282%2C%282%5E6%29%29=x\" Rewrite \"64\" as \"2%5E6\"\r
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\n" ); document.write( "\n" ); document.write( "\"6%2Alog%282%2C%282%29%29=x\" Rewrite the logarithm using the identity \"log%28b%2C%28x%5Ey%29%29=y%2Alog%28b%2C%28x%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"6%2A%281%29=x\" Evaluate \"log%282%2C%282%29%29\" to get 1 (note: \"log%28x%2C%28x%29%29=1\")\r
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\n" ); document.write( "\n" ); document.write( "\"6=x\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"x=6\"
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