document.write( "Question 1070756: Landon can climb a hill at a rate that is 2.5 mph slower than his rate coming down the hill. If it takes him 6 hours to climb the hill and 135 minutes to come down the hill what is his rate coming down?\r
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Algebra.Com's Answer #685759 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Convert 135 min to hrs:
\n" ); document.write( "\"+135%2A%28+1%2F60+%29+=+2.25+\"
\n" ); document.write( "Let \"+d+\" = the one-way distance up the hill
\n" ); document.write( "Let \"+s+\" = his rate coming down the hill
\n" ); document.write( "\"+s+-+2.5+\" = his rate going up the hill
\n" ); document.write( "--------------------------------------------
\n" ); document.write( "Going up the hill:
\n" ); document.write( "(1) \"+d+=+%28+s+-+2.5+%29%2A6+\"
\n" ); document.write( "Going down the hill:
\n" ); document.write( "(2) \"+d+=+s%2A2.25+\"
\n" ); document.write( "------------------------
\n" ); document.write( "Substitute (2) into (1)
\n" ); document.write( "(1) \"+s%2A2.25+=+%28+s+-+2.5+%29%2A6+\"
\n" ); document.write( "(1) \"+2.25s+=+6s+-+15+\"
\n" ); document.write( "(1) \"+3.75s+=+15+\"
\n" ); document.write( "(1) \"+s+=+4+\"
\n" ); document.write( "------------------------
\n" ); document.write( "His rate coming down the hill is 4 mi/hr
\n" ); document.write( "---------------------------------------
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+d+=+s%2A2.25+\"
\n" ); document.write( "(2) \"+d+=+4%2A2.25+\"
\n" ); document.write( "(2) \"+d+=+9+\" mi
\n" ); document.write( "and
\n" ); document.write( "(1) \"+d+=+%28+s+-+2.5+%29%2A6+\"
\n" ); document.write( "(1) \"+d+=+%28+4+-+2.5+%29%2A6+\"
\n" ); document.write( "(1) \"+d+=+1.5%2A6+\"
\n" ); document.write( "(1) \"+d+=+9+\" mi
\n" ); document.write( "OK
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