document.write( "Question 1070737: solve cos(theta)+sin(theta)=0 over the interval (0,2pi)
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Algebra.Com's Answer #685758 by Alan3354(69443)\"\" \"About 
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solve cos(theta)+sin(theta)=0 over the interval (0,2pi)
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\n" ); document.write( "Cos = -sin
\n" ); document.write( "cos^2 = sin^2
\n" ); document.write( "1-sin^2 = sin^2
\n" ); document.write( "2sin^2 = 1
\n" ); document.write( "sin = ħsqrt(1/2) in the quadrants where sine and cosine are opposite signs.
\n" ); document.write( "theta = 3pi/4, 7pi/4\r
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