document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1070749>Question 1070749</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve log 2x + log 8 = 3. Round to the nearest hundredth if necessary. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #685751 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=685751\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log(2x) + log(8) = 3<BR>\n" );
document.write( "log(16x) = 3 = log(10^3)<BR>\n" );
document.write( "16x = 1000<BR>\n" );
document.write( "x = 62.5<BR>\n" );
document.write( " </SPAN>\n" );
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