document.write( "Question 1070675: the johnson family and the gonzalez family went to the movies together. the johnson family bought 4 adult tickets and 2 child tickets for a total of $37. the gonzalez family bought 3 adult tickets and 4 child tickets for a total of 39$ what is the price of each type of ticket (adult and child) at this theater ? \n" ); document.write( "
Algebra.Com's Answer #685699 by addingup(3677)\"\" \"About 
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Johnsons: 4a+2c = 37
\n" ); document.write( "Gonzalez: 3a+4c = 39
\n" ); document.write( "We can solve by substitution or elimination. I'll do it by elimination because I suspect that's what your teacher expects you to do:
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\n" ); document.write( "4a+2c = 37 multiply all times -2 and add to the next equation
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\n" ); document.write( "3a+4c = 39
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\n" ); document.write( "-8a-4c = -74
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\n" ); document.write( "-5a+0c = -35
\n" ); document.write( "-5a = -35 divide both sides by -5, and remember that -/- = +
\n" ); document.write( "a = 7 the adult tickets are 7.
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\n" ); document.write( "Now we solve for c:
\n" ); document.write( "4a+2c = 37 multiply all times 3
\n" ); document.write( "3a+4c = 39 multiply all times -4 and add to the other equation
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\n" ); document.write( "12a+6c = 111
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\n" ); document.write( "-12a-16c = -156
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\n" ); document.write( "0a-10c = -45
\n" ); document.write( "-10c = -45
\n" ); document.write( "c = 4.50 this is the cost of a child's ticket
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\n" ); document.write( "Let's check:
\n" ); document.write( "Johnson: 4(7)+2(4.5) = 37 Correct
\n" ); document.write( "Gonzalez: 3(7)+4(4.5)= 39 Also correct.
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