document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1070632>Question 1070632</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the longer leg of a right triangle is 1 inch longer than the shorter leg. the hypotenuse is 9 inches longer than the shorter leg. find the side lengths of the triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #685673 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=685673\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  the longer leg of a right triangle is 1 inch longer than the shorter leg. the hypotenuse is 9 inches longer than the shorter leg. find the side lengths of the triangle. <BR>\n" );
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document.write( "shorter leg:: x<BR>\n" );
document.write( "longer leg:: x+1<BR>\n" );
document.write( "hypotenuse:: x+9<BR>\n" );
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document.write( "x^2 + (x+1)^2 = (x+9)^2<BR>\n" );
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document.write( "x^2 + x^2+2x+1 = x^2 + 18x + 81<BR>\n" );
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document.write( "x^2-16x-80 = 0<BR>\n" );
document.write( "(x-20)(x+4) = 0<BR>\n" );
document.write( "Positive solution:<BR>\n" );
document.write( "x = 20 in (shorter)<BR>\n" );
document.write( "x+1 = 21 in (longer)<BR>\n" );
document.write( "x+9 = 29 in (hypotenuse)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
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