document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1070605>Question 1070605</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the third term of an arithmetic sequence is 34 and the 15th term is -14. Determine the first 2 terms </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #685658 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=685658\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  the third term of an arithmetic sequence is 34 and the 15th term is -14. Determine the first 2 terms <BR>\n" );
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document.write( "a(1)+2d = 34<BR>\n" );
document.write( "a(1)+14d = -14<BR>\n" );
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document.write( "Subtract and solve for \"d\"::<BR>\n" );
document.write( "12d = -48<BR>\n" );
document.write( "d = -4<BR>\n" );
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document.write( "Solve for a(1)<BR>\n" );
document.write( "a(1) + 2(-8) = 34<BR>\n" );
document.write( "a(1) = 50<BR>\n" );
document.write( "a(2) = 50-4 = 46<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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