document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1070528>Question 1070528</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the dimensions of a rectangle whose length is 6 inches greater than its width. The area is 72 square inches. Show your work and explain the steps you used to find the solution in order to receive full credit. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #685650 by </B><A HREF=/tutors/aboutme.mpl?userid=DENNIS+DON><B>DENNIS DON(8)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DENNIS+DON><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=DENNIS+DON><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=685650\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let L and W be the length and width of the rectangle<BR>\n" );
document.write( "  L=W+6<BR>\n" );
document.write( "Area=L*W<BR>\n" );
document.write( "    = (W+6)*W<BR>\n" );
document.write( "    = W²+6W<BR>\n" );
document.write( "also;<BR>\n" );
document.write( "   area=72<BR>\n" );
document.write( "then;<BR>\n" );
document.write( "  W²+6W=72<BR>\n" );
document.write( "  W²+6W-72=0<BR>\n" );
document.write( "  (W-6)(W+12)=0<BR>\n" );
document.write( "   W=6 or W=-12<BR>\n" );
document.write( "BUT the dimension can't be negative<BR>\n" );
document.write( "then;<BR>\n" );
document.write( "   W=6, and<BR>\n" );
document.write( "   L=6+6<BR>\n" );
document.write( "    =12 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );