document.write( "Question 1070593: Two gasohol mixtures are available, one with 6.35% alcohol and the other with 11.28% alcohol. How many litres of the 6.35% mixture must be added to 26.1 L of the other mixture to make a final mixture containing 8.00% alcohol? \n" ); document.write( "

Algebra.Com's Answer #685648 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+x+\"$ = liters of the 6.35% mixture needed
\n" ); document.write( " $\"+.0635x+\"$ = liters of alcohol in 6.35% mixture
\n" ); document.write( " $\"+.1128%2A26.1+=+2.94408+\"$ = liters of alcohol in 11.28% mixture
\n" ); document.write( "-----------------------------------------------------------
\n" ); document.write( " $\"+%28+.0635x+%2B+2.94408+%29+%2F+%28+x+%2B+26.1+%29+=+.08+\"$
\n" ); document.write( " $\"+.0635x+%2B+2.94408+=+.08%2A%28+x+%2B+26.1+%29+\"$
\n" ); document.write( " $\"+.0635x+%2B+2.94408+=+.08x+%2B+2.088+\"$
\n" ); document.write( " $\"+.0165x+=+.85608+\"$
\n" ); document.write( " $\"+x+=+51.88364+\"$
\n" ); document.write( "51.884 liters of the 6.35% mixture is needed
\n" ); document.write( "-------------------------------------------
\n" ); document.write( "check:
\n" ); document.write( " $\"+%28+.0635x+%2B+2.94408+%29+%2F+%28+x+%2B+26.1+%29+=+.08+\"$
\n" ); document.write( " $\"+%28+.0635%2A51.884+%2B+2.94408+%29+%2F+%28+51.884+%2B+26.1+%29+=+.08+\"$
\n" ); document.write( " $\"+%28+3.29463+%2B+2.94408+%29+%2F+77.984+=+.08+\"$
\n" ); document.write( " $\"+6.23871+%2F+77.984+=+.08+\"$
\n" ); document.write( " $\"+.0799999+=+.08+\"$
\n" ); document.write( "close enough
\n" ); document.write( " \n" ); document.write( "

\n" );