document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1070575>Question 1070575</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two sides of a right triangle are 8 and 12 inches. <BR>\n" );
document.write( "    a. Find the missing side if these are the lengths of the legs. <BR>\n" );
document.write( "     b. Find the missing side if these are the lengths of a leg and hypotenuse. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #685618 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=685618\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If these are the legs, their squares, 64+144=208, which is the square of the hypotenuse.<BR>\n" );
document.write( "The hypotenuse is sqrt (208)=sqrt(16)*sqrt(13)=4 sqrt (13)<BR>\n" );
document.write( "--------------<BR>\n" );
document.write( "If one is the hypotenuse, it has to be the longer.<BR>\n" );
document.write( "12^2=8^2+ x^2<BR>\n" );
document.write( "144=64+x^2<BR>\n" );
document.write( "80=x^2<BR>\n" );
document.write( "x=4 sqrt (5) is the other leg. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );