document.write( "Question 1070529: Let ABC be a triangle such that AB= 6cm, AC=8cm and BC 10cm and M be the midpoint
\n" ); document.write( "of BC .AMDE is a square, MD and intersects AC at point F . Find the area of quadrilateral AFDE.
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Algebra.Com's Answer #685594 by KMST(5328)\"\" \"About 
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Here is triangle ABC with midsegments LM and MN
\n" ); document.write( "You know that those midsegments are parallel to
\n" ); document.write( "and half the length of the side they do not touch.
\n" ); document.write( "That makes ALMN a rectangle.
\n" ); document.write( "Line AM is the diagonal of rectangle ALMN.
\n" ); document.write( "Triangle ABC is a \"red%283%29\" times scaled-up version of the most popular 3-4-5 right triangle,
\n" ); document.write( "with side lengths in cm of
\n" ); document.write( "\"AB=3%2Ared%282%29=6\" ,
\n" ); document.write( "\"AC=4%2Ared%282%29=8\" , and
\n" ); document.write( "\"BC=5%2Ared%282%29=10\" .
\n" ); document.write( "It has a smaller acute angle ACB (opposite shorter side AB),
\n" ); document.write( "a larger acute angle ABC, and a right angle BAC (opposite longest side BC).
\n" ); document.write( "The mid segments, and AM split triangle ABC into four smaller triangles.
\n" ); document.write( "They are all 3-4-5 right triangles with sides measuring
\n" ); document.write( "\"LM=AN=NB=3cm\" ,
\n" ); document.write( "\"AL=LC=CM=4cm\" ,
\n" ); document.write( "\"BM=MC=highlight%28AM=5cm%29\" ,
\n" ); document.write( "congruent smaller acute angles (so that \"CAM=ACM\" for example),
\n" ); document.write( "and congruent larger acute angles, as well.
\n" ); document.write( "Since they tell us that \"MD and intersects AC at point F\",
\n" ); document.write( "I know to what side of segment AM square AMDE is locate,
\n" ); document.write( "and I can draw the square, like this
\n" ); document.write( " \"area%28AFDE%29=area%28AMDE%29-area%28MFA%29\"
\n" ); document.write( "\"area%28AMDE%29=AM%5E2=%285cm%29%5E2=25cm%5E2\"
\n" ); document.write( "and triangle MFA is a right triangle,
\n" ); document.write( "similar to LMA and all the other 3-4-5 triangles we looked at before,
\n" ); document.write( "because it shares the same smaller acute angle CAM with triangle LMA.
\n" ); document.write( "So, for MFA, the shorter leg to longer leg ratio is the same
\n" ); document.write( "\"MF%2FAM=3%2F4\" --> \"MF%2F%223+cm%22=3%2F4\" --> \"MF=%283%2F4%29%283cm%29\" --> \"MF=9%2F4\"\"cm%29\"
\n" ); document.write( "\"area%28MFA%29=%281%2F2%29%2AAM%2AMF\"
\n" ); document.write( "\"area%28MFA%29=%281%2F2%29%2A3%2A%289%2F4%29\"\"cm%5E2\"
\n" ); document.write( "\"area%28MFA%29=27%2F8%7D%7D%7B%7B%7Bcm%5E2\"
\n" ); document.write( "\"area%28AFDE%29=area%28AMDE%29-area%28MFA%29\"
\n" ); document.write( "\"area%28AMDE%29=25cm%5E2-3.375cm%5E2=highlight%2821.625cm%5E2%29\"
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