document.write( "Question 1070507: The numerator of a fraction is less than the denominator. If the numerator and the denominator are increased by 1, the value of a fraction becomes 3/4. What is the original fraction? \n" ); document.write( "
Algebra.Com's Answer #685589 by Theo(13342)\"\" \"About 
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n = numerator
\n" ); document.write( "d = denominator.\r
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\n" ); document.write( "\n" ); document.write( "(n + 1) / (d + 1) = 3/4\r
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\n" ); document.write( "\n" ); document.write( "this means:\r
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\n" ); document.write( "\n" ); document.write( "n + 1 = 3
\n" ); document.write( "d + 1 = 4\r
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\n" ); document.write( "\n" ); document.write( "solve for n and d and you get:\r
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\n" ); document.write( "\n" ); document.write( "n = 2
\n" ); document.write( "d = 3\r
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\n" ); document.write( "\n" ); document.write( "the original fraction is 2/3.\r
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\n" ); document.write( "\n" ); document.write( "it does not appear to be that you even needed to know that the numerator is less than the denominator, since solving the problem did not require that information.\r
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\n" ); document.write( "\n" ); document.write( "that's what i think, anyway.
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