document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1070513>Question 1070513</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find all points having an&#8203; x-coordinate of 2 whose distance from the point (&#8722;2,&#8722;4) is 5.\r<BR>\n" );
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document.write( "I know we must use distance formula,  d=&#8730;(x2-x1)^2+(y2-y1)^2 \r<BR>\n" );
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document.write( "I though the points would be (-2,-4) and (2,y)\r<BR>\n" );
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document.write( "It would look like 5=&#8730;(2-(-2))^2+(-4-y)^2\r<BR>\n" );
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document.write( "simplifies 5 = &#8730;(4)^2+(-4-y)^2\r<BR>\n" );
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document.write( "then 5 = &#8730;16+(-4-y)^2\r<BR>\n" );
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document.write( "then square to get rid of radicals (5)^2 = ( &#8730;16+(-4-y)^2 )^2\r<BR>\n" );
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document.write( "25 = 16 + (-4-y)^2<BR>\n" );
document.write( "9 = (-4 -y)^2<BR>\n" );
document.write( "then square root to get rid of power of 2<BR>\n" );
document.write( "&#8730;9 = &#8730;(-4-y)^2<BR>\n" );
document.write( "3 = -4-y<BR>\n" );
document.write( "But because +/- from squaring I would get -4-y=3 and -4-y=-3<BR>\n" );
document.write( "Solving I get -7 and -1\r<BR>\n" );
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document.write( "Which would be (2,-7) and (2,-1)\r<BR>\n" );
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document.write( "I'm not sure if I'm right or messed up entirely </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #685587 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=685587\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x coordinate of 2 and any y coordinate, 5 units away from the point (-2,-4).\r<BR>\n" );
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document.write( "You want some points  (2,y) which is 5 units distance from (-2,-4).<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28%282-%28-2%29%29%5E2%2B%28y-%28-4%29%29%5E2%29=5 ALIGN=MIDDLE  ALT=\"sqrt%28%282-%28-2%29%29%5E2%2B%28y-%28-4%29%29%5E2%29=5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Work with this equation, to solve for y.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28%284%29%5E2%2B%28y%2B4%29%5E2%29=5 ALIGN=MIDDLE  ALT=\"sqrt%28%284%29%5E2%2B%28y%2B4%29%5E2%29=5\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2816%2B%28y%2B4%29%5E2%29=5 ALIGN=MIDDLE  ALT=\"sqrt%2816%2B%28y%2B4%29%5E2%29=5\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "square both sides,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=16%2B%28y%2B4%29%5E2=25 ALIGN=MIDDLE  ALT=\"16%2B%28y%2B4%29%5E2=25\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y%2B4=0%2B-+3 ALIGN=MIDDLE  ALT=\"y%2B4=0%2B-+3\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=system%28y=-4-3%2Cor%2Cy=-4%2B3%29 ALIGN=MIDDLE  ALT=\"system%28y=-4-3%2Cor%2Cy=-4%2B3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=system%28y=-7%2Cor%2Cy=-1%29 ALIGN=MIDDLE  ALT=\"system%28y=-7%2Cor%2Cy=-1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "For the points  (2,-7) and (2,-1). </SPAN>\n" );
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