document.write( "Question 1070505: A man takes 5 hours and 20 minutes to row 6 miles up a river and back. If he can row 3 miles downstream in the same time that he can row 1 mile upstream, find the rate at which he rows and the rate of the current.
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Algebra.Com's Answer #685586 by ikleyn(52798)\"\" \"About 
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\n" ); document.write( "A man takes 5 hours and 20 minutes to row 6 miles up a river and back. If he can row 3 miles downstream in the same time
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document.write( "Let u be the rate of the boat at still water and v be the current rate (in miles-per-hour).\r\n" );
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document.write( "Then the speed of the boat downstream is (u+v) mph, \r\n" );
document.write( "while the speed of the boat  upstream is (u-v) mph.\r\n" );
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document.write( "Hence, you have these two equations for two unknowns\r\n" );
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document.write( "\"6%2F%28u%2Bv%29+%2B+6%2F%28u-v%29\" = \"5\" \"1%2F3\"      (1)   (\"A man takes 5 hours and 20 minutes to row 6 miles up a river and back\")\r\n" );
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document.write( "\"3%2F%28u%2Bv%29\" = \"1%2F%28u-v%29\"           (2)   (\"he can row 3 miles downstream in the same time that he can row 1 mile upstream\")\r\n" );
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document.write( "Simplify equation (1) in this way:\r\n" );
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document.write( "\"6%2F%28u%2Bv%29+%2B+6%2F%28u-v%29\" = \"16%2F3\"      (1') \r\n" );
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document.write( "and replace  \"6%2F%28u-v%29\"  in  (1')  by \"18%2F%28u%2Bv%29\", based on (2). You will get\r\n" );
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document.write( "\"6%2F%28u%2Bv%29+%2B+18%2F%28u%2Bv%29\" = \"16%2F3\",    or\r\n" );
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document.write( "\"24%2F%28u%2Bv%29\" = \"16%2F3\",   or   (u+v) = \"%2824%2A3%29%2F16\" = \"9%2F2\". \r\n" );
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document.write( "Then from (2)  u-v = \"%28u%2Bv%29%2F3\" = \"9%2F%282%2A3%29\" = \"3%2F2\".\r\n" );
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document.write( "You have now this system for u and v:\r\n" );
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document.write( "u + v = \"9%2F2\",    (3)\r\n" );
document.write( "u - v = \"3%2F2\".    (4)\r\n" );
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document.write( "Add the two equations. You will get\r\n" );
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document.write( "2u = \"9%2F2+%2B+3%2F2\" = \"12%2F2\" = 6.   Hence,   u = \"6%2F2\" = 3 miles per hour.\r\n" );
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document.write( "Now from (3),  v = \"9%2F2+-+3\" = \"3%2F2\" = 1.5 miles per hour.\r\n" );
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document.write( "Answer.  The boat speed in still water is 3 miles per hour.\r\n" );
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document.write( "         The current speed is 1.5 miles per hour.\r\n" );
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\n" ); document.write( "\n" ); document.write( "You can find many fully solved problems on upstream and downstream round trips with detailed solutions in lessons \r
\n" ); document.write( "\n" ); document.write( "    - Wind and Current problems \r
\n" ); document.write( "\n" ); document.write( "    - More problems on upstream and downstream round trips \r
\n" ); document.write( "\n" ); document.write( "    - Selected problems from the archive on the boat floating Upstream and Downstream \r
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\n" ); document.write( "\n" ); document.write( "Read them attentively and learn how to solve this type of problems once and for all.\r
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\n" ); document.write( "\n" ); document.write( "Also, you have this free of charge online textbook in ALGEBRA-I in this site\r
\n" ); document.write( "\n" ); document.write( "    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.\r
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\n" ); document.write( "\n" ); document.write( "The referred lessons are the part of this textbook under the section \"Word problems\", the topic \"Travel and Distance problems\".\r
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