document.write( "Question 1070367: 3x+7<1 \n" ); document.write( "
Algebra.Com's Answer #685583 by ikleyn(52781)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "3x+7<1 \n" ); document.write( "~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "3x + 7 < 1.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Subtract 7 from both sides. You will get an equivalent inequality\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "3x < 1 - 7 = -6.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Divide both sides by 3. You will get an equivalent inequality\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "x < -2.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "It is your answer.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |