document.write( "Question 1070367: 3x+7<1 \n" ); document.write( "
Algebra.Com's Answer #685583 by ikleyn(52781)\"\" \"About 
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document.write( "3x + 7 < 1.\r\n" );
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document.write( "Subtract 7 from both sides. You will get an equivalent inequality\r\n" );
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document.write( "3x < 1 - 7 = -6.\r\n" );
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document.write( "Divide both sides by 3.  You will get an equivalent inequality\r\n" );
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document.write( "x < -2.\r\n" );
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document.write( "It is your answer.\r\n" );
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