document.write( "Question 1070398: For the given pair of events A and​ B, complete parts​ (a) and​ (b) below.
\n" ); document.write( "​A: A marble is randomly selected from a bag containing 2020 marbles consisting of 1​ red, 1616 ​blue, and 33 green marbles. The selected marble is one of the green marbles.
\n" ); document.write( "​B: A second marble is selected and it is the 1 red marble in the bag.
\n" ); document.write( "a. Determine whether events A and B are independent or dependent.​ (If two events are technically dependent but can be treated as if they are independent according to the​ 5% guideline, consider them to be​ independent.)
\n" ); document.write( "b. Find​ P(A and​ B), the probability that events A and B both occur.
\n" ); document.write( "a. Choose the correct answer below.
\n" ); document.write( "A.
\n" ); document.write( "The two events are independent because the​ 5% guideline can be applied in this case.
\n" ); document.write( "B.
\n" ); document.write( "The two events are dependent because the occurrence of one affects the probability of the occurrence of the other and the​ 5% guideline cannot be applied in this case.
\n" ); document.write( "Your answer is correct.C.
\n" ); document.write( "The two events are independent because the occurrence of one does not affect the probability of the occurrence of the other.
\n" ); document.write( "D.
\n" ); document.write( "The two events are dependent because the occurrence of one affects the probability of the occurrence of the other and the​ 5% guideline can be applied in this case.
\n" ); document.write( "b. The probability that events A and B both occur is
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Algebra.Com's Answer #685520 by Boreal(15235)\"\" \"About 
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The two events are technically dependent but are treated as independent because 33<5% of 2020. Picking the green marble for all practical purposes does not affect the chances of picking a red marble.
\n" ); document.write( "The joint probability is 33/2020 (I assume there are other marbles in the bag)*(1/2019)
\n" ); document.write( "=8.09 x 10^(-6)
\n" ); document.write( "A.\r
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