document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1070385>Question 1070385</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The weight of a circular rod of a certain type is proportional to its length. A 15-foot circular rod of this type weighs 35 pounds. What is the weight, in pounds of a 21-foot circular rod of this type? <BR>\n" );
document.write( "A.) 41<BR>\n" );
document.write( "B.) 44<BR>\n" );
document.write( "C.) 47<BR>\n" );
document.write( "D.) 49<BR>\n" );
document.write( "E.) 56\r<BR>\n" );
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document.write( "I tried to read through this one one to solve it but I think the wording confused me when I tried to, please and thank you for the help!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #685476 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=685476\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 15 is to 35 as<BR>\n" );
document.write( "21 is to ---<BR>\n" );
document.write( "feet is to pounds proportion<BR>\n" );
document.write( "15/21=35/x<BR>\n" );
document.write( "cross-multiply 15x=735<BR>\n" );
document.write( "x=49 pounds.<BR>\n" );
document.write( "D. </SPAN>\n" );
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