document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=13607>Question 13607</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many liters of a 30% alcohol solution do you need to mix with 50 liters of a 60% soultion to obtain a 35% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6854 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6854\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> think of \"before\" and \"after\"\r<BR>\n" );
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document.write( "before --> got 50 litres of 60% and x litres of 30%.<BR>\n" );
document.write( "after --> got (50+x) litres of 35%.\r<BR>\n" );
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document.write( "Just looking at this, the final solution is very close to the 30% solution, so there must be a lot of the 30%, to \"drag\" the concentration down from 60%. So i am looking for a common sense answer that is a lot more than 50 litres.\r<BR>\n" );
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document.write( "So,<BR>\n" );
document.write( "(50*0.60) + (x*0.30) = (50+x)*0.35<BR>\n" );
document.write( "30 + 0.3x = 17.5 + 0.35x<BR>\n" );
document.write( "0.05x = 12.5<BR>\n" );
document.write( "--> x = 250 litres.\r<BR>\n" );
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document.write( "jon.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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