document.write( "Question 1070250: Dennis and Chris Reed leave simultaneously from the same point hiking in opposite​ directions, Dennis walking at 4 miles per hour and Chris at 2 mph. How long can they talk on their​ walkie-talkies if the​ walkie-talkies have a 15 mile​ radius?
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Algebra.Com's Answer #685392 by algebrahouse.com(1659)\"\" \"About 
You can put this solution on YOUR website!
Distance = rate x time
\n" ); document.write( "d = rt\r
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\n" ); document.write( "\n" ); document.write( "Dennis
\n" ); document.write( "rate = 4
\n" ); document.write( "time = t {left at same time}
\n" ); document.write( "d = 4t {distance = rate x time}\r
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\n" ); document.write( "\n" ); document.write( "Chris
\n" ); document.write( "rate = 2
\n" ); document.write( "time = t {left at same time}
\n" ); document.write( "d = 2t {distance = rate x time}\r
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\n" ); document.write( "\n" ); document.write( "Combined distances must be no more than 15 miles.\r
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\n" ); document.write( "\n" ); document.write( "4t + 2t = 15 {added distances and set equal to 15}
\n" ); document.write( "6t = 15 {combined like terms}
\n" ); document.write( "t = 2.5 hours {divided each side by 6}\r
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\n" ); document.write( "\n" ); document.write( ".5 hours is 30 minutes.\r
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\n" ); document.write( "\n" ); document.write( "They can talk for 2 hours and 30 minutes,
\n" ); document.write( "or 2.5 hours as requested for rounding.
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For more help from me, visit: www.algebrahouse.com


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